100b^2+6=55

Solution for 100b^2+6=55 equation:

100b^2+6=55

We move all terms to the left:

100b^2+6-(55)=0

We add all the numbers together, and all the variables

100b^2-49=0

a = 100; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·100·(-49)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19600}=140$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-140}{2*100}=\frac{-140}{200}
=-7/10
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+140}{2*100}=\frac{140}{200}
=7/10
$